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author | John W. Eaton <jwe@octave.org> |
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date | Sat, 07 Mar 2009 10:41:27 -0500 |
parents | 48d213be5e0e |
children | 853f96e8008f |
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## Copyright (C) 2000, 2005, 2007, 2008 Daniel Calvelo ## Copyright (C) 2009 Jaroslav Hajek ## ## This file is part of Octave. ## ## Octave is free software; you can redistribute it and/or modify it ## under the terms of the GNU General Public License as published by ## the Free Software Foundation; either version 3 of the License, or (at ## your option) any later version. ## ## Octave is distributed in the hope that it will be useful, but ## WITHOUT ANY WARRANTY; without even the implied warranty of ## MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU ## General Public License for more details. ## ## You should have received a copy of the GNU General Public License ## along with Octave; see the file COPYING. If not, see ## <http://www.gnu.org/licenses/>. ## -*- texinfo -*- ## @deftypefn {Function File} {} sortrows (@var{a}, @var{c}) ## Sort the rows of the matrix @var{a} according to the order of the ## columns specified in @var{c}. If @var{c} is omitted, a ## lexicographical sort is used. By default ascending order is used ## however if elements of @var{c} are negative then the corresponding ## column is sorted in descending order. ## @end deftypefn ## Author: Daniel Calvelo, Paul Kienzle ## Adapted-by: jwe function [s, i] = sortrows (m, c) default_mode = "ascend"; other_mode = "descend"; if (issparse (m)) error ("sortrows: sparse matrices not yet supported"); endif ## If the sort is homogeneous, we use the built-in faster algorithm. if (nargin == 1) i = __sort_rows_idx__ (m, default_mode); elseif (all (c > 0)) i = __sort_rows_idx__ (m(:,c), default_mode); elseif (all (c < 0)) i = __sort_rows_idx__ (m(:,-c), other_mode); else ## Otherwise, fall back to the old algorithm for ii = 1:length (c); if (c(ii) < 0) mode{ii} = other_mode; else mode{ii} = default_mode; endif endfor indices = abs(c(:)); ## Since sort is 'stable' the order of identical elements will be ## preserved, so by traversing the sort indices in reverse order we ## will make sure that identical elements in index i are subsorted by ## index j. indices = flipud (indices); mode = flipud (mode'); i = [1:size(m,1)]'; for ii = 1:length (indices); [trash, idx] = sort (m(i, indices(ii)), mode{ii}); i = i(idx); endfor endif s = m(i,:); endfunction %!shared x, idx %! [x, idx] = sortrows ([1, 1; 1, 2; 3, 6; 2, 7], [1, -2]); %!assert (x, [1, 2; 1, 1; 2, 7; 3, 6]); %!assert (idx, [2; 1; 4; 3]);