Mercurial > hg > octave-nkf
view scripts/audio/lin2mu.m @ 12575:d0b799dafede
Grammarcheck files for 3.4.1 release.
author | Rik <octave@nomad.inbox5.com> |
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date | Mon, 04 Apr 2011 15:33:46 -0700 |
parents | 605ed5bbb643 |
children | 72c96de7a403 |
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## Copyright (C) 1995-2011 John W. Eaton ## ## This file is part of Octave. ## ## Octave is free software; you can redistribute it and/or modify it ## under the terms of the GNU General Public License as published by ## the Free Software Foundation; either version 3 of the License, or (at ## your option) any later version. ## ## Octave is distributed in the hope that it will be useful, but ## WITHOUT ANY WARRANTY; without even the implied warranty of ## MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU ## General Public License for more details. ## ## You should have received a copy of the GNU General Public License ## along with Octave; see the file COPYING. If not, see ## <http://www.gnu.org/licenses/>. ## -*- texinfo -*- ## @deftypefn {Function File} {} lin2mu (@var{x}, @var{n}) ## Convert audio data from linear to mu-law. Mu-law values use 8-bit ## unsigned integers. Linear values use @var{n}-bit signed integers or ## floating point values in the range -1 @leq{} @var{x} @leq{} 1 if ## @var{n} is 0. ## ## If @var{n} is not specified it defaults to 0, 8, or 16 depending on ## the range of values in @var{x}. ## @seealso{mu2lin, loadaudio, saveaudio} ## @end deftypefn ## Author: Andreas Weingessel <Andreas.Weingessel@ci.tuwien.ac.at> ## Created: 17 October 1994 ## Adapted-By: jwe function y = lin2mu (x, n) if (nargin == 1) range = max (abs (x (:))); if (range <= 1) n = 0; elseif (range <= 128) n = 8; warning ("lin2mu: no precision specified, so using %d", n); else n = 16; endif elseif (nargin == 2) if (n != 0 && n != 8 && n != 16) error ("lin2mu: N must be either 0, 8 or 16"); endif else print_usage (); endif ## Transform real and n-bit format to 16-bit. if (n == 0) ## [-1,1] -> [-32768, 32768] x = 32768 * x; elseif (n != 16) x = 2^(16-n) .* x; endif ## Determine sign of x, set sign(0) = 1. sig = sign(x) + (x == 0); ## Take absolute value of x, but force it to be smaller than 32636; ## add bias. x = min (abs (x), 32635) + 132; ## Find exponent and fraction of bineary representation. [f, e] = log2 (x); y = 64 * sig - 16 * e - fix (32 * f) + 335; endfunction